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❄️ Vacuum Cooling

Cooling Time Calculation Guide

How to estimate cooling time based on product type, mass, initial temperature and target temperature. The cooling time calculator provides a preliminary estimat

📅 2026-02-10
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Key takeaways
Vacuum cooling removes heat by boiling a small part of the product's own water at low pressure. Batch times measured on CVF machines: leafy greens 28°C→2°C in 25 min, mushrooms 25°C→4°C in 20 min, broccoli 30°C→2°C in 30 min, cooked food 90°C→10°C in 8 min. The chamber is pulled to ≤660 Pa while the cold trap runs at -10 to -5°C, so the vapour leaves the chamber instead of loading the vacuum pump.

The Heat Balance Behind a Cooling Cycle

The time required to cool a batch of product in a vacuum cooler depends on the total heat that must be removed and the cooling capacity of the system. The basic formula is: Q = m × Cp × ΔT + Lv × Δm, where Q is total heat (kJ), m is product mass (kg), Cp is specific heat capacity (kJ/kg·K), ΔT is temperature difference (K), Lv is latent heat of vaporization (2,257 kJ/kg) and Δm is mass of evaporated water (kg).

The formula has two parts and they behave differently. The first term, m × Cp × ΔT, is sensible heat: it depends only on how much product there is and how far its temperature must fall. The second, Lv × Δm, is the heat carried away by water leaving the product as vapour. Because the latent heat of vaporization is large, this term is what makes vacuum cooling work — the product cools itself by evaporating part of its own moisture.

Reference Cycle Times

ProductInitial TemperatureTarget TemperatureTime
Leafy Vegetables28°C2°C25 minutes
Mushrooms25°C4°C20 minutes
Broccoli30°C2°C30 minutes
Cooked Food90°C10°C8 minutes

The produce rows start from ambient temperature, in the 25–30°C band typical of freshly harvested vegetables. The cooked food row starts from a hot product at 80–90°C, which carries more sensible heat per kilogram but also evaporates faster.

What Shortens or Lengthens a Cycle

An estimate is a starting point, because several variables move it in either direction:

  • Temperature span. A larger ΔT adds to the sensible heat term and lengthens the cycle.
  • Product structure. Leafy and porous products release moisture freely; dense or sugar-rich products restrict the vapour path and take longer.
  • Load and packaging. Closely stacked trays, sealed films or heavy cartons block vapour escape; the same mass loaded loosely cools faster.
  • Equipment condition. Pump displacement and condensing capacity set the achievable rate; a worn door seal or a fouled condenser lowers it.

Using the Estimate

Treat the calculated time as a planning figure and confirm it with a trial on the actual product and load, since load density, batch weight and product variety all shift the result. A practical figure should therefore be stated per product and per batch: where the material and the batch weight differ, the cycle time differs with them.

Frequently Asked Questions

How long does vacuum cooling take?

For fresh produce 20–30 min: leafy greens 28°C→2°C in 25 min, mushrooms 25°C→4°C in 20 min, broccoli 30°C→2°C in 30 min. Cooked food from 90°C to 10°C takes about 8 min per batch. Time scales with batch mass and water content.

What determines the cooling time?

The total heat to remove: Q = m × Cp × ΔT + Lv × Δm, with Lv = 2,257 kJ/kg. In practice the limits are how fast the chamber reaches ≤660 Pa, the cold-trap evaporating temperature (-10 to -5°C) and the compressor capacity.

Why does cycle time get longer after months of use?

Almost always air entering the chamber: a damaged door gasket, a valve seal that no longer closes, or a weld pinhole. The leak prevents the chamber from holding the set vacuum, less water evaporates, and every batch takes longer.
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